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x^2-400x+300=0
a = 1; b = -400; c = +300;
Δ = b2-4ac
Δ = -4002-4·1·300
Δ = 158800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{158800}=\sqrt{400*397}=\sqrt{400}*\sqrt{397}=20\sqrt{397}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-400)-20\sqrt{397}}{2*1}=\frac{400-20\sqrt{397}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-400)+20\sqrt{397}}{2*1}=\frac{400+20\sqrt{397}}{2} $
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